500 câu trắc nghiệm Kinh tế lượng – 7C
Tổng hợp 500 câu trắc nghiệm + tự luận Kinh tế lượng (Elementary Statistics). Tất cả các câu hỏi trắc nghiệm + tự luận đều có đáp án. Nội dung được khái quát trong 13 phần, mỗi phần gồm 3 bài kiểm tra (A, B, C). Các câu hỏi trắc nghiệm + tự luận bám rất sát chương trình kinh tế lượng, đặc biệt là phần thống kê, rất phù hợp cho các bạn củng cố và mở rộng các kiến thức về Kinh tế lượng. Các câu hỏi trắc nghiệm + tự luận của phần 7C bao gồm:
SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question.
Provide an appropriate response.
1) When testing hypothesis about a mean, the decision must be made as to the distribution to be used. Discuss the decision process used to decide whether z or t or neither is the proper distribution.
Use the z distribution for n \( \le \) 30, if the parent population is normally distributed and \(\sigma \) is known; or for n > 30, if \(\sigma \) is known. Use the t distribution for n \( \le \) 30, if the parent population is normally distributed and \(\sigma \) is not known; or for n > 30 if \(\sigma \) is not known. However, if the parent population is not normally distributed and n \( \le \) 30, neither distribution should be use.
Solve the problem.
2) What do you conclude about the claim below? Do not use formal procedures or exact calculations. Use only the rare event rule and make a subjective estimate to determine whether the event is likely.
Claim: A company claims that the proportion of defectives among a particular model of computers is 4%. In a shipment of 200 such computers, there are 10 defectives.
If the defective rate were really 4%, one could easily obatained 10 defectives among 200 computers by change; this is not improbable. Therefore, by the rare event rule, we have no reason to reject the claim that the rate of defectives is 4%.
3) Write the claim that is suggested by the given statement, then write a conclusion about the claim. Do not use symbolic expressions or formal procedures; use common sense.
Of a group of 1000 people suffering from arthritis, 500 receive acupuncture treatment and 500 receive a placebo. Among those in the placebo group, 24% noticed an improvement, while of those receiving acupuncture, 44% noticed an improvement.
The claim is the proportion who notice an improvement in the treatment group is greater than the proportion who notice an improvement in the placebo group, i.e., that acupuncture is more effective than a placebo. If the acupuncture treatment and the placebo were equally effective, it would be very unlikely that the percentage of people in the group who notice an improvement in the acupuncture group would be so much greater than the percentage of the people who notice an improvement in the placebo group. The claim that acupuncture is more effective than a placebo therefore senses reasonable.
MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Solve the problem.
Indentify the null hypothesis H0 and the alternative hypothesis H1.
4) A researcher claims that the amounts of acetaminophen in a certain brand of cold tablets have a standard deviation different from the \(\sigma \) = 3.3 mg claimed by the manufacturer.
○ H0: \(\sigma \) \( \ge \) 3.3 mg; H1: \(\sigma \) < 3.3 mg ○ H0: \(\sigma \) \( \le \) 3.3 mg; H1: \(\sigma \) > 3.3 mg
○ H0: \(\sigma \) \( \ne \) 3.3 mg; H1: \(\sigma \) = 3.3 mg
● H0: \(\sigma \) = 3.3 mg; H1: \(\sigma \) \( \ne \) 3.3 mg
Assume that the data has a normal distribution and the number of observations is greater than fifty. Find the critical z value used to test a null hypothesis.
5) \(\alpha \) = 0.08; H1 is \(\mu \) \( \ne \) 3.24
○ 1.41
○ ±1.41
● ±1.75
○ 1.75
Use the given information to find the z-value: \(z = \frac{{\hat p – p}}{{\sqrt {\frac{{\hat pp}}{n}} }}\)
6) The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25, and the sample statistics include n = 662 drowning deaths of children with 30% of them attributable to beaches.
○ 2.72
○ -2.88
○ -2.72
● 2.88